Students in a class were surveyed about the number of children in their families. the results of the survey are shown in the table. two surveys are chosen at random from the group of surveys. after the first survey is chosen, it is returned to the stack and can be chosen a second time. what is the probability that the first survey chosen indicates four children in the family and the second survey indicates one child in the family?

1/5

Step-by-step explanation:

Since the surveys are chosen with replacement (the first one is replaced before the second is chosen), the events are independent.  This means that the probability of both together is the product of each event's probability.

The probability of choosing a survey that indicates 4 children in the family is 8/60, since there are 8 surveys with 4 children out of a total of (9+18+22+8+3) = 60 surveys.

The probability of choosing a survey that indicates 1 child is 9/60, since there are 9 surveys with 1 child out of a total of 60.

Together this gives us

8/60(9/60) = 72/360 = 1/5

homozygous. one is homozygous, while two is heterozygous.

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.