Which of the following functions f(x) represent the order pairs: {(-2,-7), (-1,-4), (0,-1), (1,2), (2,5) a. f(x)=2x b. f(x)=3x-1 c. f(x)=-3x+5 d. f(x)=3x+5

B.f(x) = 3x-1

Step-by-step explanation:

{(-2,-7), (-1,-4), (0,-1), (1,2), (2,5) are solutions of f(x) = 3x-1

Plug in

(-2,-7): f(x) = 3(-2) -1 = -6 - 1 = -7

(-1,-4): f(x) = 3(-1) -1 = -3 - 1 = -4

(0,-1): f(x) = 3(0) -1 =  - 1

(1,2): f(x) = 3(1) -1 = 3 - 1 = 2

(2,5): f(x) = 3(2) -1 = 6 - 1 = 5

step-by-step explanation:

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

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