In simplest radical form, what are the solutions to the quadratic equation 0 = –3x^2 – 4x + 5?

x = - ±

Step-by-step explanation:

given a quadratic equation in the form ax² + bx + c = 0

We can solve using the quadratic formula

with a = - 3, b= - 4 and c = 5

x = ( 4 ± ) / - 6

  = ( 4 ± ) / - 6

  = ( 4 ± ) / - 6

  = (4 ± 2) / - 6

  = - ±

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions