Write a quadratic function whose graph has the given characteristics x-intercepts: -4,2 point on graph (0,-9)

y = (9/8)(x +4)(x -2)

When the x-intercepts are "a" and "b", you know factors of the function are (x-a) and (x-b). So, we can write the function as ...

... y = k(x -(-4))(x -2) = k(x +4)(x -2) . . . . . for some scale factor k

We can find k using the given point.

... -9 = k(0 +4)(0 -2) = -8k

Dividing by -8 gives ...

... 9/8 = k

The desired function is ...

... y = (9/8)(x +4)(x -2)

... = (9/8)(x² +2x -8)

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

the surface area is 124cm²

step-by-step explanation:

length: 4cm

width: 9cm

height:   2cm