What is the average rate of change of the function over the interval x = 0 to x = 5? f(x)=4^2x+1 enter your answer, as a simplified fraction,

838860

Plug in x = 0 to find y = f(x)

f(x) = 4^(2x+1)

f(0) = 4^(2*0+1)

f(0) = 4

The point (0,4) is on the function curve

Plug in x = 5 and compute

f(x) = 4^(2x+1)

f(5) = 4^(2*5+1)

f(5) = 4194304

The point (5, 4194304) is on the function curve

Once you have these two points, you use the slope formula to compute the average rate of change

m = (y2-y1)/(x2-x1)

m = (4194304 - 4)/(5-0)

m = 838860

The slope of the line through the two points found earlier is m = 838860, so this is the average rate of change on f(x) for the interval from x = 0 to x = 5.

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step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.