Point e is the midpoint of side bc of parallelogram abcd (labeled counterclockwise) and ae ∩ bd =f. find the area of abcd if the area of △bef is 3 cm2.

Explanation:

Since here ABCD is the parallelogram.

Where E is the mid point of the line segment BC.

And, F is the intersection point of the segments AE and BD,

Also,  Area of △BEF is 3 .

We have to find Area of parallelogram ABCD.

Since,In  ΔBEF  and ΔACD,

∠ADF=∠EBF ( because AD ║ BE )

∠DFA = ∠BFE (vertically opposite angle)

Thus, By AA similarity postulate,

,

Thus,

But, AD = 2 BE,

Therefore,   = 4/1

Thus, area of Δ ADF =

Similarly,

Now, let the area of the triangle AFB = x

Thus, x + 12 = 2(x+3) ( because the area of the ΔADB = 2(area of ΔBAE) )

⇒ x = 6

Therefore, area of ΔAFB= 6

⇒ area of ΔABD = 12 + 6 = 18

By the definition of diagonal of parallelogram,

Area of parallelogram ABCD = 2× area of Δ ABD= 2 × 18 = 36

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

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