Drag and drop the correct answer into each box to complete the proof. parallelogram k l m n where k n is parallel to l m and k l is parallel to m n given: parallelogram klmn prove: ∠n≅∠l and ∠m≅∠k

Parallelogram KLMN Given

KL¯¯¯¯¯∥NM¯¯¯¯¯¯¯ and KnllLM Definition of parallelogram

m∠K+m∠N=180°

m∠L+m∠M=180°

m∠K+m∠L=180° Same-Side Interior Angles Theorem

m∠K+m∠N=m∠K+m∠L

m∠L+m∠M=m∠K+m∠L Substitution Property of Equality

m∠N=m∠L

m∠M=m∠K Subtraction Property of Equality

∠N≅∠L

and ∠M≅∠K

Angle Congruence Postulate

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351.23

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