Write the slope-intercept form of the equation of the line described. through: (2,-2), parrallel to y=-1/2x-4

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0) or (0,y)

When lines are parallel, their slopes have to be the SAME.

Since the given line's slope is -1/2, the parallel line's slope is also -1/2

y = -1/2x + b

To find "b", plug in the point (2, -2) into the equation

y = -1/2x + b

-2 = -1/2(2) + b

-2 = -1 + b     Add 1 on both sides

-1 = b

y = -1/2x - 1

m a t h w a y. c o m

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?