Pqr has medians qm and pm that intersect at z. if zm = 4, find qz and qm.

value of QZ = 8 units and QM =  12 units.

Step-by-step explanation:

Given: In triangle PQR has medians QM and PN that intersect at Z.

If ZM = 4 units.

In the figure given below;  second median divided the two triangles formed by the first median in the ratio 2:1.

We have to find the value of QZ and QM;

QZ:ZM = 2: 1

⇒

Substitute the value of ZM =4 units and solve for QZ;

Multiply both sides by 4 we get;

Now, calculate QM;

QM = QZ+ZM = 8 + 4 = 12 units.

Therefore, the value of QZ and QM are; 8 units and 12 units

b

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b

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7

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14

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6

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step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18