Atotal of 626 tickets were sold for the school play. they were either adult tickets or student tickets. there were 74 fewer student tickets sold than adult tickets. how many adult tickets were sold?

351 adults and 275 students

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 626 tickets were purchased, then s+a=626.

We also know that 74 fewer student tickets then adult tickets. So s+76=a, the number of student tickets plus 76 will be the number of adult tickets.

We will solve by substituting one equation into the other. We substitute a=76+s into s+a=626. Simplify and isolate the variable a.

s+a=626

s+76+s=626

2s+76=626

2s+76-76=626-76

2s=550

s=275

This means that 275 students attended and 351 adults attended since 275+351=626.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

there is no question content here, but you for the free points! : d