Iwill award brainliest! the patronete winery's tastiest wine must have a 12% alcohol content. how many gallons of wine with a 9% alcohol content must be mixed with 3,000 gallons of wine with a 15% alcohol content in order to achieve the desired 12% alcohol content?

3000 gallons of 12 percent is required

Step-by-step explanation:

We can use the formula

percentage * amount + percentage * amount =  percentage*total amount

We have 9 percent and 15 percent wine that we are mixing to get 12 percent wine.

We are adding g gallons and 3000 gallons to get a total of (g+3000) gallons

Substituting this information in

.09 *g + .15 * 3000 = .12 (g+3000)

Distribute

.09g +450 = .12g+360

Subtract .9g from each side

.09g-.09g +450 = .12g-0.09g+360

450 = .03g + 360

Subtract 360 from each side

450-360 = .03g

90 =.03g

Divide each side by .03

90/.03 = .03g/03

3000 = g

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

it is a secret for it not to be compromised sorry

step-by-step explanation: