Rearrange the formula v = 1 3 πr2h for h. a) h = 3v πr2 b) h = v 3πr2 c) h = 3πr2 v d) h = πr2 3v

A)h = 3V/ πr^2

Step-by-step explanation:

V = 1/ 3 πr^2h

Multiply each side by 3

3V = 3*1/ 3 πr^2h

3V = πr^2h

Divide each side by  πr^2 to isolate h

3V /πr^2 = πr^2/πr^2 h

3V /πr^2 =  h

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!