Which is the approximate solution for the system of equations x+5y=10 and 3x+y=1?

Step-by-step explanation:

Given system of equations :

x+5y=10 and 3x+y=1.

Let us solve the system of equation by substitution.

Solving second equation 3x+y=1 for y first.

3x+y=1.

Subtracting 3x from both sides, we get

3x-3x+y=1-3x

y = 1-3x.

Substituting y=1-3x in first equation x+5y=10, we get

x+ 5(1-3x) = 10.

x + 5 -15x =10

-14x +5 = 10.

Subtracting 5 from both sides, we get

-14x +5-5 = 10-5

-14x =5

Dividing by -14 on both sides, we get

-14x/-14=5/-14

x= -0.36.

Plugging x=-0.36 in second equation y=1-3x, we get

y = 1-3(-0.36) = 1+1.08 = 2.08.

y=1/4x-4

step-by-step explanation: