A town's population is 53,075. about 100 people move out of the town each month. each month, 200 people on average move into town. a nearby town has a population of 55,825. it has no one moving in and an average of 175 people moving away every month. in about how many months will the populations of the towns be equal? write an equation to model the situation. then solve the equation and answer the question.

If we let m represent the number of months, then the population increase of the first town is 100m and its decrease is 200m. The population decrease of the second town is 175 m.

We want to find m such that the increases and decreases make the towns' populations equal. We add the increases and subtract the decreases to the base population in each case.

... first town population = second town population

... 53075 -100m +200m = 55825 -175m . . . . . the model equation

Solution

... 100m = 2750 -175m . . . . . collect terms, subtract 53075

... 275m = 2750 . . . . . . . . . . add 175m

... m = 10 . . . . . . . . . . . . . . . . . divide by 275

The populations will be equal in 10 months.

answer: 1inch=7days  

12inch=12*7=84days

step-by-step explanation: