Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0h(-3) =h(-2)=h(0)=

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

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Use PEMDAS:

PParentheses first

EExponents (ie Powers and Square Roots, etc.)

MDMultiplication and Division (left-to-right)

ASAddition and Subtraction (left-to-right)

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Put the values of x to the equation of the function h(x):

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.