A) find a polynomial, which, when added to the polynomial 5x2–3x–9, is equivalent to: 18 b) find a polynomial, which, when added to the polynomial 5x2–3x–9, is equivalent to: 0

a)

b)

Step-by-step explanation:

a) Let the required polynomial be p(x).

We have the relation, + p(x) = 18

i.e. p(x) = 18

i.e. p(x) =

b) Let the required polynomial be q(x).

We have the relation, + q(x) = 0

i.e. q(x) = 0

i.e. q(x) =

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5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form