Me. explanation needed in algebraic form: a painting, square in shape, is placed in a wooden frame with width of 10% of the length of the side of the painting. the painting was enlarged by 10%. by what percent is the new frame bigger than the original frame if the width of the frame remains the same?

the new frame is bigger than the original frame by 10%

Step-by-step explanation:

Let the length of the original frame be l,

then it's width is (10% of l)=×l

                                           =

hence area of original frame=A=length×width

                                               =

now the length of frame is enlarged by 10%

new lenght of frame=l+10%×l

                                 =l+×l

                                  =×l

width of new frame==

area of new frame=length×width

                              =

percent change=((area of new frame-area of old frame)×100)÷area of old frame

=10%

4th option is correct xy=-10

if this was to u plzz mark me the brainliest

i dont know sorry

step-by-step explanation: