Determine between which consecutive integers the real zeros of f(x)=2x^2-5x+1 are located a. between 0& 1 and 1& 2 c. between 0& 1 and 2& 3 b. between -1& 0 and 2& 3 d. between 1& 2 and 2& 3

c. between 0&1 and 2&3

Step-by-step explanation:

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: