Write the equation in standard form. then factor the left side of the equation.? 2x2 = 28 – x a.) (2x + 7)(x – 4) = 0 b.) (2x – 7)(x + 4) = 0 c.) (2x + 4)(x + 7) = 0 d.) (2x – 4)(x + 7) = 0

2x² = 28 - x

2x²+x-28=0

2x²+8x-7x-28=0

2x(x+4)-7(x+4)=0

(x+4)(2x-7)=0

(2x-7)(x+4)=0

B.) (2x - 7)(x + 4) = 0

answer: 43/157

this is the answer and if you try to prove me wrong your a meanie

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752