F(x)=4x2−8x−60 f(x)=4(x2−2x−15) f(x)=4(x−5)(x+3) whts the true statement of f(x) a the zeros of f(x) are –5 and 3. b the vertex of the graph of f(x) is (–5, 3). c the vertex of the graph of f(x) is (5, –3). d the zeros of f(x) are 5 and –3.

D

Step-by-step explanation:

No such thing as a vertex of a graph... Eliminate B and C. Try f(3) = 4(3-5)(3+3) is not zero eliminate A. So answer must be D. Check: f(-3) has factor -3+3 = 0. f(5) has factor 5-5 = 0.

step-by-step explanation:

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