Identify an equation in point-slope form for the line parallel to y=5x+2 that passes through (-6,-1)

y = 5x + 29

Step-by-step explanation:

y=5x+2

Given equation is in the form of y=mx+b

Where m is the slope = 5

and b is the y intercept = 2

When the lines are parallel then their slopes are equal

So the slope of parallel line is also 5 (m=5)

Given that the line passes through (-6,-1)

We use point slope formula

y-y1= m (x-x1)

m=5, x1= -6, y1=-1

Plug in all the values

y - (-1) = 5(x-(-6))

y + 1= 5 (x+6)

y + 1= 5x + 30

Subtract 1 on both sides

y = 5x + 29

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )