In parallelogram abcd , diagonals ac⎯⎯⎯⎯⎯ and bd⎯⎯⎯⎯⎯ intersect at point e, be=x2−21 , and de=4x . what is bd ? __units

BD= 56units

Step-by-step explanation:

  Since, Diagnols of a parallelogram  bisect each other.

Therefore in parallelogram ABCD where AC and BD are the diagnols wich intersect at Point E, we have, BE=DE

Therefore, x^2-21=4x

x^2-21-4x=0

x^2-4x-21=0

x^2-7x-3x-21=0      [middle term splitting]

x(x-7)+3(x-7)=0

(x+3)(x-7)=0

Hence, x= -3 and x= 7

Since x cannot be negative because no side can have negative values

Therefore, we have x=7

Now, BD= BE+DE      [Since E is the intersecting point of BD]

            = 4x+x^2-21

            = 4(7)+7^2-21

            =28+49-21= 56 units

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step-by-step explanation: