Asemicircle is cut out of a rectangular paperboard 24in long and 18n wide, as shown below. what is the perimeter of the paperboard that remains after the semicircle is removed? (use the value 3.14 for π , and do not round your answer. be sure to include the correct unit in your answer.)

Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in

Step-by-step explanation:

Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.

Length = 24 in

Width = 18 in

Radius of the semi circle = Half of the width of the paperboard = = 9 in

1) Circumference of the semi circle = π*radius

= 3.14*9

= 28.26 in

2) Perimeter of the paperboard that remains after the semicircle is removed

= Top + Left + Bottom + Right Circumference of the semi circle

= 24 + 18 + 24 + 28.26

= 94.26 in

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day