Write an expression (4x-2)*6(2x+7) in the standard form of a quadratic expression, ax^2+bx+c. what are the values of the coefficients of each term and the constant term?

see explanation

Step-by-step explanation:

given (4x - 2) × 6(2x + 7), then

= 6(4x - 2)(2x + 7) ← expand factors using FOIL

= 6(8x² + 28x - 4x - 14)

= 6(8x² + 24x - 14) ← distribute

= 48x² + 144x - 84 ← in standard form

with a = 48, b= - 144, c = - 84

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632