Which is an equation of the line that is perpendicular to 3x+y=-5 and passes through the point (3, -7)?

y+7=1/3(x-3) in point slope

y=1/3x-8 in slope intercept form

Step-by-step explanation:

First put 3x+y=5 in slope-intercept form (y=mx+b)

y=-3x+5

Give that the slope is -3 the perpendicular slope would be 1/3

now using the points (3.-7)

y+7=1/3(x-3) in point slope

y=1/3x-8 in slope intercept form

Put it in Slope - Intercept Form:

3x + y = -5

-3x         -3x

y = -3x - 5

Now plug in the ordered pair that is given:

(3, -7)

y = -3x - 5

-7 = -3(3) - 5

-7 = -9 - 5

-7 = -14

NO, it's false

Hi, really really sorry if I am incorrect...

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step-by-step explanation:

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry