Asoccer team hopes to win at least 3 games for every 2 lost during the season. if there are 15 games scheduled, how many games can the team lose and still achieve its goal

This team can lose 6 games and still achieve this goal.

Step-by-step explanation:

In order to find this, we can create a proportion and solve by cross multiplying. The proportion should compare amount of losses to total games.

Ratio = Total  

2/5 = x/15

Now cross multiply

15*2 = 5x

30 = 5x

6 = x

This means the team can lose 6 games and still keep the necessary ratio.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.