Acard is chosen at random from a deck of 52 cards. it is replaced, and a second card is chosen. what is the probability that both cards chosen are jacks? a.) 1/26 b.) 1/13 c.) 1/169 d.) 2/13

C.) 1/169

Step-by-step explanation:

There are 4 jacks in a deck of 52 cards

The probability the first card is a jack

4/52 = 1/ 13

Since we replace the card

The probability the second card is a jack

4/52 = 1/ 13

To get the probability that we get a jack then a jack, we multiply the probabilities

1/13 * 1/13 = 1/169

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

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