What is the greatest possible integer value of x for whichsquare root of x-5 is an imaginary number?

4

Step-by-step explanation:

√x imaginary if and only if x < 0

√(x-5) imaginary ifi x-5 < 0

x<5

4 is the largest integer < 5.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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