Can someone me on this one, ? denis and dasha solve this problem in two different ways. the perimeter of a rectangle is 54 centimeters. its length is 6 centimeters. what is its width? use the drop-down menus to complete the sentences below.

21

Step-by-step explanation:

since its a rectangle there are two lengths of six. If you add them together you get 12. subtract the total perimeter of 54 by the 12 and get 42. Since there is 2 sides left divide by 2. You should get 21 for the width of the rectangle

thats wrong

Step-by-step explanation:

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )