What are the zeroes of the polynomial function f(x)=x^3+2x^2-x-2

 -2, -1, 1

Step-by-step explanation:

f(x) = x³ + 2x² - x - 2

 0 = x³ + 2x²   - x - 2

    = x²(x + 2)  -1(x + 2)

   = (x² - 1) (x + 2)

   = (x - 1) (x + 1) (x + 2)

0 = x - 1       0 = x + 1        0 = x + 2

1 = x           -1 = x             -2 = x

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