At a horse show, ribbons are awarded for first, second, third, and fourth places. there are 16 horses in the show. how many different arrangements of four horses are possible?

43680 different arrangements are possible.

Step-by-step explanation:

The total number of horses are :16

We have to find different arrangement of four horses

Since, we have to find arrangements means we will use permutation

So, the required arrangement will be:

Now, using:

Here, n= 16 and r=4 on substituting the values we get:

Cancel out the common term that is 12! we get:

After simplification we get: 43680

Hence, 43680 different arrangements are possible.

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42

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hope this !