What are the real and complex solutions of 0=x^4+3x^2-4

(2i,0) (-2i,0)

(1,0) (-1,0).

Step-by-step explanation:

The graph below shows that there are only 2 real solutions at x = 1 and x = - 1

Expressed as points, these two are (1,0) and (-1,0). However that is not the complete answer. There are 2 complex points.

y = x^4 + 3x^2 - 4

y = (x^2 - 1)(x^2 + 4)

These two binomials can be equated to 0

================

step-by-step explanation:

i am not sure sorry : c

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)