The specifications for a new cardboard container require that the width for the container be 4 inches less than the length and the height be 1 inch less than twice the length. a. write a polynomial function that models the volume of the container in terms of its length. b. write an equation if the volume must be 2208 cubic inches. c. find the dimensions of the new container.

c) Length = 12, width = 8 and height = 23.

Step-by-step explanation:

Let the length be x, then the width = x - 4 and the height = 2x - 1.

a) The polynomial is x(x - 4)(2x - 1)

b) x(x - 4)(2x - 1) = 2208

c) x(x - 4)(2x - 1) - 2280 = 0

2x^3 - 9x^2 + 4x - 2280 = 0

I'll use graphical software to find a solution for this. Its easily obtained online.

There is one real root and its x = 12.

So the dimensions of the box are L = 12, W = 8 and H = 23 inches.

a) V(l)=2l³-9l²+4l

b) 2208=2l³-9l²+4l

c) 12in × 8in × 23in

Step-by-step explanation:

Got a 100% on edge 2020

the answer is true.

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.