Can somebody me with this. see the attachment.

48

Let x represent the distance OC. Then CD = x+2, and DP = 16-x. The radius of circle P is ...

... CD +DP = (x+2) +(16-x) = 18

The radius of circle O is ..

... OC + CD = (x) + (x +2) = 2x+2

The length OP is ...

... OC + CP = (x) + (18) = x+18.

Now, the perimeter of ΔAOP is ...

... radius of circle O + radius of circle P + OP = 80

... = (2x+2) + 18 + (x+18) = 3x+38 = 80

Then x is ...

... x = (80 -38)/3 = 14

and the radius of circle O is

... 2x +2 = 2·14 +2 = 30

The desired sum is ...

... OB + BP = (radius of circle O) + (radius of circle P) = 30 + 18

... OB + BP = 48

chiken

step-by-step explanation:

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.