Atourist starts to walk up a mountain path that is 31 miles long at the rate of 4 miles per hour. after walking for a while, he gets tired and decides to get a taxi. the taxi gets him to the top travelling at a constant speed of 50 mph. if the tourist reaches the destination 2 hours after he started, what distance does he have to pay the cab driver for?

Let the Distance traveled by the tourist by walking be : D miles

Given : Tourist walks at a rate of 4 Miles per Hour

Given : The Total Distance of Mountain Path = 31 Miles

Distance traveled by the tourist by hiring a Taxi is : (31 - D) Miles

Given : The Taxi travels at a constant speed of 50 miles per hour

Given : The Tourist reaches the destination 2 Hours after he started

Time taken by Walking + Time Taken by travelling in Taxi = 2 Hours

⇒ Distance traveled by the tourist by walking = 6 Miles

⇒ Distance traveled by the tourist by hiring a taxi = (31 - 6) = 25 Miles

⇒ The Distance for which tourist has to pay for cab driver is 25 Miles

The distance traveled by taxi = 25 miles

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration

• At constant velocity motion:

the speed of vo = v = constant

acceleration = a = 0

An equation of constant velocity motion

x = distance = m

v = speed = m / s

t = time = seconds

x1, x2 = distance traveled

t1, t2 = travel time

1 = tourist, 2 = taxi

Total distance = x1 + x2

then:

The distance of the elevator

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resultant velocity

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the average velocity

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i'm not sure i quite understand, could you provide more information?