4z 27 +x5 y14 if x, y and z each represent a different digit from 0 to 9, what is the value of (x)(y)(z)?

4(1)(2) = 8

Step-by-step explanation:

Consider the addition in the unit digits.

z +7 + 5 = z + 12

and the unit digit of this sum should be 4 since the unit digit of the answer is 4.

Also, since z is a number from 0 to 9, the only possibility is z = 2.

Hence, the unit digit sum is 14 and the carry over is 1.

Now, consider the tenth digits sum with previous carry over 1.

1 + 4 + 2 + x = y1

7 + x = y1

Since, x and y are numbers from 0 to 9, the only possibility is x = 4 and hence

7 + 4 = y1

11 = y1

y = 1

So, x = 4, y = 1, z = 2

(x)(y)(z) = (4)(1)(2) = 8

use substitution to solve each system of equations. y = x + 5 3x + y = 25 62/87,21 y = x + 5 3x + y = 25 substitute x + 5 for y in the second equation. substitute the solution for x into either equation to find y. the solution is (5, 10)

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step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!