Theorem: the segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. a two-column proof of the theorem is shown, but the proof is incomplete. a triangle with vertices a is at 6, 8. b is at 2, 2. c is at 8, 4. segment de with point d on side ab and point e is on side bc. statement reason the coordinates of point d are (4, 5) and coordinates of point e are (5, 3) by the midpoint formula length of segment de is square root of 5 and length of segment ac is 2 multiplied by the square root of 5 by the distance formula segment de is half the length of segment ac by substitution slope of segment de is −2 and slope of segment ac is −2 segment de is parallel to segment ac slopes of parallel lines are equal which of the following completes the proof? by definition of congruence addition property of equality by construction by the slope formula

 By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

In which A≡(6,8), B≡(2,2) and C≡(8,4)

And, D and E are the mid points of the line segments AB and BC respectively.

Prove: DE║AC and DE = AC/2

Proof:

Since, And, D and E are the mid points of the line segments AB and BC respectively.

Therefore, By mid point theorem,

coordinate of D are

Coordinate of E are  

By the distance formula,

By the slope formula,

Slope of AC =

Slope of DE =  

            Statement                                              Reason

1. The coordinate of D are (4,5)  and           1. By the midpoint formula

the coordinate of  E are (5,3)

2. The length of DE = √5                            2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the                3. By the slope formula

slope of AC = -2

4. DE║AC                                                   4. Slopes of parallel lines are equal

your answer is d 2,500

step-by-step explanation: