If u=(1+i√3) and v=(1-i√3), what is uv?

4

Step-by-step explanation:

You may recognize these as factors of the difference of two squares:

... a² -b² = (a+b)(a-b)

where a=1 and b=i√3.

Then the product is ...

... 1² -(i√3)² = 1 - 3i² = 1 +3 = 4

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Of course, i = √-1, so i² = -1.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

what is the graph

step-by-step explanation: