Marco starts reading a 350-page book at 9 a. m. the number of pages p marco has left to read t hours after 9 a. m. is modeled by the function p(t) = 350 - 45t. during which of the following time periods does marco read the same number of pages he reads between 11 a. m. and 1 p. m.? select all that apply a. 9 a. m. to 11 a. m. b. 11 a. m. to 12 noon c. 12: 30 p. m. to 1: 30 p. m. d. 2 p. m. to 4 p. m. e. 1: 30 p. m. to 3: 30 p. m.

A, D, and E

Step-by-step explanation:

So the function 350-45t for t hours means that he reads 45 pages every hour. So, going from 11 AM to 1 PM is two hours. Since his reading pace doesn't change, we just have to look for an answer that has a difference of two answers. The only answers that have a difference of two hours are A, D, and E.

answer: f = 32.2m

step-by-step explanation: that is the answer

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!