Graph y+6=45(x+3) using the point and slope given in the equation

Check attached graph of the line in picture

Step-by-step explanation:

Step-by-step explanation:

We have been given an equation y+6=45(x+3) in point slope form.

It says to use the point and slope from given equation to create the graph.

So compare equation y+6=45(x+3) with point slope formula

y-y1=m(x-x1)

we see that m=45, x1=-3 and y1=-6

Hence first point is at (-3,-6)

slope m=45 is positive so to find another point, previous point will move 45 units up then 1 unit right and reach at the location (-2,39).

Now we just graph both points (-3,-6) and  (-2,39) and join them by a straight line. Final graph will look like the line in attached graph.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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