Ois the centre of a circle pq is a chord and pt is a tangent at p if angle poq is 70° then find angle tpq

< TPQ = 145 degrees

Step-by-step explanation:

< QPO = (180 - 70)/2 = 55 degrees ( base angle of an isosceles triangle).

< OPT = 90 degrees ( OP is a radius to point of contact of the tangent).

Therefore < TPQ = < QPO + < OPT

=  55 + 90

= 145 degrees

51-50

step-by-step explanation:

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17