Can someone plz me with these 2 problems 1.a tourist was planning a trip by car for travelling at some constant speed for 2.5 hours. however, he found that if he increases the speed by 20 km/h he can cover the same distance in 30 minutes less time than it was planned. what was the planned speed of the tourist, in km/h? 2.a jet ski with average speed of 60 mph left a pier by the river upstream. fifteen minutes after its motor broke, and it began drifting downstream for 3 hours and 45 minutes until reached another pier, which was 2 miles away down the river from the original pier. what is the rate of the current, in mph?

1.  r = 80 km/h

2. The current is flowing at 4.25 mph

Step-by-step explanation:

1.  Distance = rate * time

Distance = r * 2.5

If he increase the rate by 20  = (r+20),

the time is 30 minute = .5 hours less  =(t-.5)

The time was 2.5 hours  = (2.5-.5) = 2 hours

Distance = (r+20) 2 hours

The distance is the same so we set the equations equal

2.5r = 2 * (r+20)

Distribute

2.5r = 2r +40

Subtract 2r from each side

2.5r -2r = 2r-2r +40

.5r = 40

Divide by .5

.5r /.5 = 40/.5

r = 80 km/h

2.  Distance = rate * time

rate = 60-r    time = 15 minutes/60 minute = .25 hours

Distance = (60-r) * .25

where r is the rate of the current

While drifting it is affected by the current only

Now time = 3 hours 45 minutes = 3 .75 hours

Distance is the the distance it traveled while jetskiing plus 2 miles

Distance +2 = r* (3.75)

Substituting for distance

(60-r) * .25 +2 = 3.75 r

Distribute

15 -.25r +2 = 3.75r

Combine like terms

17 -.25r = 3.75r

Add .25r to each side

17-.25r +.25r = 3.75r +.25r

17 = 4r

Divide by 4

17/4 = 4r/4

4.25 =r

The current is flowing at 4.25 mph

125 yards

step-by-step explanation:

i take 75 plus 50.

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step-by-step explanation: