Can someone answer this fast? the determinant of matrix a is shown below.

Replace x and y with the given values, solve the 4 equations in Matrix B:

4(3)+2 = 12+2 = 14

8(1) = 8

7-2(3) = 7-6 = 1

-7(1) +8 = -7+8 = 1

Now using the letter locations from Matrix A solve ad-bc:

14*1 - 8*1 = 14 - 8 = 6

The answer is 6

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11