No is divisible by 7 if n is divided by 2 3 4 5 the remainder is 1 what is the smallest value that n could b

The required number is 301

Step-by-step explanation:

Let the number be N.

The number when divided by 2, 3, 4, 5 leaves the remainder 1 so, N-1 is divisible by 2, 3, 4, 5. So, possible cases of N-1 are : multiples of  l.c.m.(2, 3,4, 5) = multiples of 60

25

step-by-step explanation:

where is the rest of the

step-by-step explanation: