rewrite as a single logarithm.

ln\frac{(x-3)^5}{x^2}[/tex]

Step-by-step explanation:

First use the exponent property  alnb=ln(b)^a

Then use the difference property that is lna-lnb= ln(a/b)

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8