Plz solve the equations for x. 1)ax+bx=13 2)ax+5=cx 3)ax+b=dx−1

Hello there!

ax + bx = 13

We want to start by factorizing out the variable x

x(a + b) = 13

Then divide both sides by a+b

x( a + b)/a + b = 13/a+b

x =

2)

ax + 5 = cx

Should start by adding -cx on both sides

ax + 5 - cx = cx - cx

ax + 5 - cx = 0

ax - cx = 0 - 5

ax - cx = -5

Then again, we need to factor out x because there's two of them

x( a - c) = -5

Then divide both sides by a-c

x(a - c)/ a - c = -5/a - c

x =

3)

ax + b = dx - 1

Start by adding -dx on both sides

ax + b - dx = dx - 1 - dx

ax - dx + b = -1

ax - dx = -1 - b

Here we go again, factor out x

x( a - d) = -b - 1

x =

I hope these answers help. As always, it is my pleasure to help students like you. Let me know if you have additional questions.

c. prove the lengths are the same.

step-by-step explanation:

you need to prove the segments are congruent. congruent segments have the same length. find the lengths of the segments using the distance formula, and compare them.

answer: c. prove the lengths are the same.

the answer is. -82562234434584

step-by-step explanation: