Alinear function has a slope of 5/2 and passes through the point 0,6 . what is the equation of the line?

y  =  x^ 3  -  17 x ^2 /2  +  15 x

Step-by-step explanation:

y - Y1 = m(x - X1)

y - 6 = 5/2(x - 0) --- POINT SLOPE FORM

y - 6 = 5/2x - 0

  + 6            + 6

y = 5/2x + 6 --- SLOPE INTERCEPT FORM

-5/2x  -5/2x

-5/2x + y = 6 --- STANDARD FORM

Hope this helps you!!! :)

lol

step-by-step explanation:

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)