1) classify the following polynomial by degree. p(p - 5) + 6 a) binomial b) trinomial c) linear d) quadratic 2) classify the following polynomial by number of terms. 5m^2 - 3m^2 a) linear b) binomial c) quadratic d) monomial 3) classify the following polynomial by number of terms. 2 + 3x^3 - 2 a) binomial b) monomial c) constant d) cubic 4) classify the following polynomial by degree. -3 + 3x - 3x a) trinomial b) linear c) constant d) monomial

1. D quadratic

2.  D monomial

3.  B) Monomial

4. C) Constant

Step-by-step explanation:

1) Classify the following polynomial by degree. p(p - 5) + 6

p(p - 5) + 6

Distribute

p^2 -5p +6

This has 3 terms so it is a trinomial and is of the second order so it is quadratic.  We are to classify it by degree (order) so it is quadratic

A) Binomial

B) Trinomial  

C) Linear

D) Quadratic

2) Classify the following polynomial by number of terms. 5m^2 - 3m^2

5m^2 - 3m^2

2m^2

The polynomial as written has 2 terms, but can be simplified to one term.  I always had students simplify first before classifying

I would call it monomial.  Check your notes if your instructor does it differently.

A) Linear

B) Binomial  

C) Quadratic

D) Monomial

3) Classify the following polynomial by number of terms. 2 + 3x^3 - 2

2 + 3x^3 - 2

Again, I teach simplify first

2-2 goes away

3x^3  

This has 1 term so it is a monomial

A) Binomial

B) Monomial

C) Constant  

D) Cubic

4) Classify the following polynomial by degree. -3 + 3x - 3x

-3 + 3x - 3x

Again I teach simplify first, so 3x-3x goes away

-3

This is a constant term

A) Trinomial

B) Linear

C) Constant

D) Monomial

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

the 3rd on is correct

step-by-step explanation: