Write the equation of a line in slope-intercept form that passes through the point (9,-6) and is parallel to the line 3y+33=2x

Let’s first turn 3y+33=2x into slope-intercept form.

3y+33=2x

Subtract 33 on both sides

3y=2x-33

Divide 3 on both terms of the right side of the equation.

y=2/3x-11

When lines are parallel to each other, it means that the slopes are the same.

So, the slope of the equation will be 2/3

This is how your equation is looking so far: y=2/3x

Because this line passes through the point (9,-6), plug in 9 for x and plug in -6 for y in the equation.

-6=2/3(9)

2/3 times 9 is 18/3, which is equal to 6.

What plus 6 is equal to -6? -12

So, -12 would be your y-intercept.

This is what your final equation would look like:

y=2/3x-12

Hope I helped!

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it