Determine the quadrant when the terminal side of the angle lies according to the following conditions: sin (t) > 0, cos (t) < 0. quadrant iii quadrant i quadrant ii quadrant iv

C. Quadrant II.

Step-by-step explanation:

Given the condition on sin and cosine is sin(t) greater than 0 and cosine less than 0.

sin(t) is greater than 0 only in two quadrant first and second only .

cos(t) is less than 0 0nly in two quadrant first and third only.

but we are given that cos(t) less than zero and sin(t) greater than 0.

Hence, the correct answer is second quadrant in which sin(t)  positive and cos(t)  negative .

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer